From: Brian Guilbault <guil9964@nova.gmi.edu>
Subject: Checking Linked Rooms

This command should work now. It's still terribly inefficient, but it
works.  Don't forget to add your calls in interpreter.c and you are all
set.

ACMD(do_roomlink)         /* Shows all exits to a given room */
  int door = 0, i = 0, room_num = 0;  {

  one_argument(argument, buf);
  room_num = real_room(atoi(buf));

  if (room_num == NOWHERE) {
    send_to_char("There is no room with that number.\r\n", ch);
    return;
  } else {
    for (i = 0; i <= top_of_world; i++) {
      for (door = 0; door < NUM_OF_DIRS; door++) {
        if (world[i].dir_option[door] &&

    world[i].dir_option[door]->to_room == room_num) {
          sprintf(buf2, "Exit %s from room %d.\r\n", dirs[door],


world[i].number);
          send_to_char(buf2, ch);
        }
      }
    }
  }
}