& pop()
 
  Syntax: pop([<object>], [<position>])
 
  This function returns an item from the caller's stack and removes it 
  from the stack. If <position> is specified, it returns the item from 
  that position in the stack (items in the stack are numbered with 0 
  being the most recently push()ed item) and removes it, otherwise, it 
  returns position 0. If <object> is specified and you control it, 
  then it returns an item from <object>'s stack.
  
  See Also: lstack(), empty(), items(), peek(), push(), OBJECT STACK